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1353055002373 is a prime number
BaseRepresentation
bin10011101100001000010…
…111001101111100000101
311210100110201200211021001
4103230020113031330011
5134132024040033443
62513330200253301
7166516651520524
oct23541027157405
94710421624231
101353055002373
11481911302798
1219a293471231
139a791a68979
14496b991c4bb
15252e1ac5d4d
hex13b085cdf05

1353055002373 has 2 divisors, whose sum is σ = 1353055002374. Its totient is φ = 1353055002372.

The previous prime is 1353055002323. The next prime is 1353055002389. The reversal of 1353055002373 is 3732005503531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1326074311809 + 26980690564 = 1151553^2 + 164258^2 .

It is an emirp because it is prime and its reverse (3732005503531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1353055002373 - 29 = 1353055001861 is a prime.

It is a super-2 number, since 2×13530550023732 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1353055002323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 676527501186 + 676527501187.

It is an arithmetic number, because the mean of its divisors is an integer number (676527501187).

Almost surely, 21353055002373 is an apocalyptic number.

It is an amenable number.

1353055002373 is a deficient number, since it is larger than the sum of its proper divisors (1).

1353055002373 is an equidigital number, since it uses as much as digits as its factorization.

1353055002373 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 141750, while the sum is 37.

The spelling of 1353055002373 in words is "one trillion, three hundred fifty-three billion, fifty-five million, two thousand, three hundred seventy-three".