Base | Representation |
---|---|
bin | 11001001101000001… |
… | …01011010010000101 |
3 | 1021220222222010020211 |
4 | 30212200223102011 |
5 | 210202414030424 |
6 | 10114400155421 |
7 | 656211422251 |
oct | 144640532205 |
9 | 37828863224 |
10 | 13531001989 |
11 | 581399707a |
12 | 2757608b71 |
13 | 13783bcb6b |
14 | 9250b1261 |
15 | 542d90b94 |
hex | 32682b485 |
13531001989 has 2 divisors, whose sum is σ = 13531001990. Its totient is φ = 13531001988.
The previous prime is 13531001971. The next prime is 13531002013. The reversal of 13531001989 is 98910013531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9615371364 + 3915630625 = 98058^2 + 62575^2 .
It is a cyclic number.
It is not a de Polignac number, because 13531001989 - 229 = 12994131077 is a prime.
It is a super-2 number, since 2×135310019892 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13531001929) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6765500994 + 6765500995.
It is an arithmetic number, because the mean of its divisors is an integer number (6765500995).
Almost surely, 213531001989 is an apocalyptic number.
It is an amenable number.
13531001989 is a deficient number, since it is larger than the sum of its proper divisors (1).
13531001989 is an equidigital number, since it uses as much as digits as its factorization.
13531001989 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 29160, while the sum is 40.
The spelling of 13531001989 in words is "thirteen billion, five hundred thirty-one million, one thousand, nine hundred eighty-nine".
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