Base | Representation |
---|---|
bin | 11001001101000010… |
… | …00101101110010101 |
3 | 1021221000011121211002 |
4 | 30212201011232111 |
5 | 210202431012133 |
6 | 10114402353045 |
7 | 656212353101 |
oct | 144641055625 |
9 | 37830147732 |
10 | 13531110293 |
11 | 5813a60488 |
12 | 275765b785 |
13 | 137842a24c |
14 | 9250dc901 |
15 | 542db2ce8 |
hex | 326845b95 |
13531110293 has 2 divisors, whose sum is σ = 13531110294. Its totient is φ = 13531110292.
The previous prime is 13531110277. The next prime is 13531110317. The reversal of 13531110293 is 39201113531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12400604164 + 1130506129 = 111358^2 + 33623^2 .
It is a cyclic number.
It is not a de Polignac number, because 13531110293 - 24 = 13531110277 is a prime.
It is a super-2 number, since 2×135311102932 (a number of 21 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13531110233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6765555146 + 6765555147.
It is an arithmetic number, because the mean of its divisors is an integer number (6765555147).
Almost surely, 213531110293 is an apocalyptic number.
It is an amenable number.
13531110293 is a deficient number, since it is larger than the sum of its proper divisors (1).
13531110293 is an equidigital number, since it uses as much as digits as its factorization.
13531110293 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2430, while the sum is 29.
The spelling of 13531110293 in words is "thirteen billion, five hundred thirty-one million, one hundred ten thousand, two hundred ninety-three".
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