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13531322143 = 122326774133
BaseRepresentation
bin11001001101000011…
…11001011100011111
31021221000120101102101
430212201321130133
5210203004302033
610114411105531
7656214224533
oct144641713437
937830511371
1013531322143
115814095669
1227577422a7
1313784a27c1
14925155bc3
15542e0597d
hex32687971f

13531322143 has 8 divisors (see below), whose sum is σ = 13550722848. Its totient is φ = 13511937504.

The previous prime is 13531322111. The next prime is 13531322171. The reversal of 13531322143 is 34122313531.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13531322143 - 25 = 13531322111 is a prime.

It is a super-2 number, since 2×135313221432 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13531322543) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3271905 + ... + 3276037.

It is an arithmetic number, because the mean of its divisors is an integer number (1693840356).

Almost surely, 213531322143 is an apocalyptic number.

13531322143 is a deficient number, since it is larger than the sum of its proper divisors (19400705).

13531322143 is a wasteful number, since it uses less digits than its factorization.

13531322143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8033.

The product of its digits is 6480, while the sum is 28.

Adding to 13531322143 its reverse (34122313531), we get a palindrome (47653635674).

The spelling of 13531322143 in words is "thirteen billion, five hundred thirty-one million, three hundred twenty-two thousand, one hundred forty-three".

Divisors: 1 1223 2677 4133 3273971 5054659 11064041 13531322143