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1353134131143 = 32271986981103
BaseRepresentation
bin10011101100001101000…
…101000100011111000111
311210100200020120222112020
4103230031011010133013
5134132204314144033
62513342104254223
7166521632224614
oct23541505043707
94710606528466
101353134131143
11481951a39373
1219a2b5a71373
139a7a5282622
14496c623950b
15252e8a066b3
hex13b0d1447c7

1353134131143 has 8 divisors (see below), whose sum is σ = 1812126766848. Its totient is φ = 898115458104.

The previous prime is 1353134131133. The next prime is 1353134131229. The reversal of 1353134131143 is 3411314313531.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1353134131143 - 24 = 1353134131127 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1353134131123) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 993489871 + ... + 993491232.

It is an arithmetic number, because the mean of its divisors is an integer number (226515845856).

Almost surely, 21353134131143 is an apocalyptic number.

1353134131143 is a deficient number, since it is larger than the sum of its proper divisors (458992635705).

1353134131143 is a wasteful number, since it uses less digits than its factorization.

1353134131143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1986981333.

The product of its digits is 19440, while the sum is 33.

Adding to 1353134131143 its reverse (3411314313531), we get a palindrome (4764448444674).

The spelling of 1353134131143 in words is "one trillion, three hundred fifty-three billion, one hundred thirty-four million, one hundred thirty-one thousand, one hundred forty-three".

Divisors: 1 3 227 681 1986981103 5960943309 451044710381 1353134131143