Base | Representation |
---|---|
bin | 11001001101000100… |
… | …01100111110011101 |
3 | 1021221000201110011021 |
4 | 30212202030332131 |
5 | 210203014332031 |
6 | 10114412524141 |
7 | 656215010005 |
oct | 144642147635 |
9 | 37830643137 |
10 | 13531402141 |
11 | 581413a784 |
12 | 2757780651 |
13 | 137850003a |
14 | 925177005 |
15 | 542e1e511 |
hex | 32688cf9d |
13531402141 has 4 divisors (see below), whose sum is σ = 13760748000. Its totient is φ = 13302056284.
The previous prime is 13531402123. The next prime is 13531402169. The reversal of 13531402141 is 14120413531.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13531402141 - 27 = 13531402013 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13531402111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 114672841 + ... + 114672958.
It is an arithmetic number, because the mean of its divisors is an integer number (3440187000).
Almost surely, 213531402141 is an apocalyptic number.
It is an amenable number.
13531402141 is a deficient number, since it is larger than the sum of its proper divisors (229345859).
13531402141 is an equidigital number, since it uses as much as digits as its factorization.
13531402141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 229345858.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 13531402141 its reverse (14120413531), we get a palindrome (27651815672).
The spelling of 13531402141 in words is "thirteen billion, five hundred thirty-one million, four hundred two thousand, one hundred forty-one".
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