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13531425465 = 351627554453
BaseRepresentation
bin11001001101000100…
…10010101010111001
31021221000202122011010
430212202102222321
5210203021103330
610114413224133
7656215135005
oct144642225271
937830678133
1013531425465
115814156258
122757792049
13137850a83c
14925181705
15542e263b0
hex326892ab9

13531425465 has 16 divisors (see below), whose sum is σ = 21663626688. Its totient is φ = 7212311616.

The previous prime is 13531425463. The next prime is 13531425533. The reversal of 13531425465 is 56452413531.

It is a happy number.

It is not a de Polignac number, because 13531425465 - 21 = 13531425463 is a prime.

It is a super-2 number, since 2×135314254652 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (13531425461) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 252822 + ... + 301631.

It is an arithmetic number, because the mean of its divisors is an integer number (1353976668).

Almost surely, 213531425465 is an apocalyptic number.

13531425465 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

13531425465 is a deficient number, since it is larger than the sum of its proper divisors (8132201223).

13531425465 is a wasteful number, since it uses less digits than its factorization.

13531425465 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 556088.

The product of its digits is 216000, while the sum is 39.

Adding to 13531425465 its reverse (56452413531), we get a palindrome (69983838996).

The spelling of 13531425465 in words is "thirteen billion, five hundred thirty-one million, four hundred twenty-five thousand, four hundred sixty-five".

Divisors: 1 3 5 15 1627 4881 8135 24405 554453 1663359 2772265 8316795 902095031 2706285093 4510475155 13531425465