Base | Representation |
---|---|
bin | 111111000000101101… |
… | …0100111001111101011 |
3 | 110221021100110120120121 |
4 | 1332001122213033223 |
5 | 4204111144123111 |
6 | 142055110504111 |
7 | 12530144264605 |
oct | 1760132471753 |
9 | 427240416517 |
10 | 135315223531 |
11 | 52428a09254 |
12 | 22284965037 |
13 | c9b6131507 |
14 | 6799384175 |
15 | 37be7d4871 |
hex | 1f816a73eb |
135315223531 has 2 divisors, whose sum is σ = 135315223532. Its totient is φ = 135315223530.
The previous prime is 135315223529. The next prime is 135315223543. The reversal of 135315223531 is 135322513531.
It is a weak prime.
It is an emirp because it is prime and its reverse (135322513531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 135315223531 - 21 = 135315223529 is a prime.
It is a super-2 number, since 2×1353152235312 (a number of 23 digits) contains 22 as substring.
Together with 135315223529, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (135315223031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67657611765 + 67657611766.
It is an arithmetic number, because the mean of its divisors is an integer number (67657611766).
Almost surely, 2135315223531 is an apocalyptic number.
135315223531 is a deficient number, since it is larger than the sum of its proper divisors (1).
135315223531 is an equidigital number, since it uses as much as digits as its factorization.
135315223531 is an evil number, because the sum of its binary digits is even.
The product of its digits is 40500, while the sum is 34.
Subtracting 135315223531 from its reverse (135322513531), we obtain a square (7290000 = 27002).
The spelling of 135315223531 in words is "one hundred thirty-five billion, three hundred fifteen million, two hundred twenty-three thousand, five hundred thirty-one".
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