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135315513433 is a prime number
BaseRepresentation
bin111111000000101101…
…1101110000001011001
3110221021101000022020201
41332001123232001121
54204111232412213
6142055121022201
712530146613032
oct1760133560131
9427241008221
10135315513433
1152429097041
1222284a84961
13c9b6203459
14679941ba89
1537be8406dd
hex1f816ee059

135315513433 has 2 divisors, whose sum is σ = 135315513434. Its totient is φ = 135315513432.

The previous prime is 135315513397. The next prime is 135315513503. The reversal of 135315513433 is 334315513531.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 72227637504 + 63087875929 = 268752^2 + 251173^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-135315513433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 135315513392 and 135315513401.

It is not a weakly prime, because it can be changed into another prime (135315513733) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67657756716 + 67657756717.

It is an arithmetic number, because the mean of its divisors is an integer number (67657756717).

Almost surely, 2135315513433 is an apocalyptic number.

It is an amenable number.

135315513433 is a deficient number, since it is larger than the sum of its proper divisors (1).

135315513433 is an equidigital number, since it uses as much as digits as its factorization.

135315513433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 121500, while the sum is 37.

The spelling of 135315513433 in words is "one hundred thirty-five billion, three hundred fifteen million, five hundred thirteen thousand, four hundred thirty-three".