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135320407 = 1249108343
BaseRepresentation
bin10000001000011…
…01001101010111
3100102121222200221
420010031031113
5234120223112
621232215211
73232130065
oct1004151527
9312558627
10135320407
116a426252
123939a507
132205c361
1413d87035
15bd2ee07
hex810d357

135320407 has 4 divisors (see below), whose sum is σ = 135430000. Its totient is φ = 135210816.

The previous prime is 135320401. The next prime is 135320417. The reversal of 135320407 is 704023531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 135320407 - 27 = 135320279 is a prime.

It is a super-2 number, since 2×1353204072 = 36623225101291298, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (135320401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52923 + ... + 55420.

It is an arithmetic number, because the mean of its divisors is an integer number (33857500).

Almost surely, 2135320407 is an apocalyptic number.

135320407 is a deficient number, since it is larger than the sum of its proper divisors (109593).

135320407 is a wasteful number, since it uses less digits than its factorization.

135320407 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 109592.

The product of its (nonzero) digits is 2520, while the sum is 25.

The square root of 135320407 is about 11632.7299891298. The cubic root of 135320407 is about 513.3983065095.

Adding to 135320407 its reverse (704023531), we get a palindrome (839343938).

The spelling of 135320407 in words is "one hundred thirty-five million, three hundred twenty thousand, four hundred seven".

Divisors: 1 1249 108343 135320407