Base | Representation |
---|---|
bin | 10000001000011… |
… | …11010101011001 |
3 | 100102122102122101 |
4 | 20010033111121 |
5 | 234121012423 |
6 | 21232323401 |
7 | 3232164343 |
oct | 1004172531 |
9 | 312572571 |
10 | 135329113 |
11 | 6a431847 |
12 | 393a3561 |
13 | 220632ca |
14 | 13d8a293 |
15 | bd327ad |
hex | 810f559 |
135329113 has 2 divisors, whose sum is σ = 135329114. Its totient is φ = 135329112.
The previous prime is 135329107. The next prime is 135329119. The reversal of 135329113 is 311923531.
It is a balanced prime because it is at equal distance from previous prime (135329107) and next prime (135329119).
It can be written as a sum of positive squares in only one way, i.e., 102576384 + 32752729 = 10128^2 + 5723^2 .
It is a cyclic number.
It is not a de Polignac number, because 135329113 - 25 = 135329081 is a prime.
It is equal to p7663051 and since 135329113 and 7663051 have the same sum of digits, it is a Honaker prime.
It is not a weakly prime, because it can be changed into another prime (135329119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67664556 + 67664557.
It is an arithmetic number, because the mean of its divisors is an integer number (67664557).
Almost surely, 2135329113 is an apocalyptic number.
It is an amenable number.
135329113 is a deficient number, since it is larger than the sum of its proper divisors (1).
135329113 is an equidigital number, since it uses as much as digits as its factorization.
135329113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2430, while the sum is 28.
The square root of 135329113 is about 11633.1041858998. The cubic root of 135329113 is about 513.4093163045.
The spelling of 135329113 in words is "one hundred thirty-five million, three hundred twenty-nine thousand, one hundred thirteen".
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