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135331336453 = 373936194527
BaseRepresentation
bin111111000001001100…
…0000101000100000101
3110221022110210012100111
41332002120011010011
54204124310231303
6142100444113021
712530431244215
oct1760230050405
9427273705314
10135331336453
1152437014115
122228a235771
13c9b95835a1
14679b57a245
1537c0e18b6d
hex1f82605105

135331336453 has 4 divisors (see below), whose sum is σ = 135367534720. Its totient is φ = 135295138188.

The previous prime is 135331336333. The next prime is 135331336463. The reversal of 135331336453 is 354633133531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-135331336453 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (135331336463) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18093525 + ... + 18101002.

It is an arithmetic number, because the mean of its divisors is an integer number (33841883680).

Almost surely, 2135331336453 is an apocalyptic number.

It is an amenable number.

135331336453 is a deficient number, since it is larger than the sum of its proper divisors (36198267).

135331336453 is an equidigital number, since it uses as much as digits as its factorization.

135331336453 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 36198266.

The product of its digits is 437400, while the sum is 40.

Adding to 135331336453 its reverse (354633133531), we get a palindrome (489964469984).

The spelling of 135331336453 in words is "one hundred thirty-five billion, three hundred thirty-one million, three hundred thirty-six thousand, four hundred fifty-three".

Divisors: 1 3739 36194527 135331336453