135333422041 has 4 divisors (see below), whose sum is σ = 135338147812. Its totient is φ = 135328696272.

The previous prime is 135333422033. The next prime is 135333422071. The reversal of 135333422041 is 140224333531.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 140224333531 = 30941 ⋅4531991.

It can be written as a sum of positive squares in 2 ways, for example, as 30856435600 + 104476986441 = 175660^2 + 323229^2 .

It is a cyclic number.

It is not a de Polignac number, because 135333422041 - 2³ = 135333422033 is a prime.

It is a super-3 number, since 3×135333422041³ (a number of 34 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 135333421994 and 135333422012.

It is not an unprimeable number, because it can be changed into a prime (135333422071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2319666 + ... + 2377291.

It is an arithmetic number, because the mean of its divisors is an integer number (33834536953).

Almost surely, 2^135333422041 is an apocalyptic number.

It is an amenable number.

135333422041 is a deficient number, since it is larger than the sum of its proper divisors (4725771).

135333422041 is an equidigital number, since it uses as much as digits as its factorization.

135333422041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4725770.

The product of its (nonzero) digits is 25920, while the sum is 31.

Adding to 135333422041 its reverse (140224333531), we get a palindrome (275557755572).

The spelling of 135333422041 in words is "one hundred thirty-five billion, three hundred thirty-three million, four hundred twenty-two thousand, forty-one".