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13533425341 = 67201991423
BaseRepresentation
bin11001001101010011…
…11010111010111101
31021221011112020110121
430212221322322331
5210204024102331
610114524134541
7656241134362
oct144651727275
937834466417
1013533425341
1158152a1847
122758397451
131378a5abb7
14925542469
155431bdc11
hex326a7aebd

13533425341 has 4 divisors (see below), whose sum is σ = 13735416832. Its totient is φ = 13331433852.

The previous prime is 13533425329. The next prime is 13533425357. The reversal of 13533425341 is 14352433531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13533425341 - 29 = 13533424829 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13533425297 and 13533425306.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13533425371) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 100995645 + ... + 100995778.

It is an arithmetic number, because the mean of its divisors is an integer number (3433854208).

Almost surely, 213533425341 is an apocalyptic number.

It is an amenable number.

13533425341 is a deficient number, since it is larger than the sum of its proper divisors (201991491).

13533425341 is an equidigital number, since it uses as much as digits as its factorization.

13533425341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 201991490.

The product of its digits is 64800, while the sum is 34.

Adding to 13533425341 its reverse (14352433531), we get a palindrome (27885858872).

The spelling of 13533425341 in words is "thirteen billion, five hundred thirty-three million, four hundred twenty-five thousand, three hundred forty-one".

Divisors: 1 67 201991423 13533425341