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1353342740173 is a prime number
BaseRepresentation
bin10011101100011001100…
…000110110011011001101
311210101012210010102022121
4103230121200312123031
5134133121220141143
62513414515412541
7166530044326324
oct23543140663315
94711183112277
101353342740173
11481a49771426
1219a3538b4151
139a809562318
1449705c1d0bb
152530beb17ed
hex13b198366cd

1353342740173 has 2 divisors, whose sum is σ = 1353342740174. Its totient is φ = 1353342740172.

The previous prime is 1353342740129. The next prime is 1353342740179. The reversal of 1353342740173 is 3710472433531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 841369576644 + 511973163529 = 917262^2 + 715523^2 .

It is an emirp because it is prime and its reverse (3710472433531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1353342740173 - 221 = 1353340643021 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1353342740179) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 676671370086 + 676671370087.

It is an arithmetic number, because the mean of its divisors is an integer number (676671370087).

Almost surely, 21353342740173 is an apocalyptic number.

It is an amenable number.

1353342740173 is a deficient number, since it is larger than the sum of its proper divisors (1).

1353342740173 is an equidigital number, since it uses as much as digits as its factorization.

1353342740173 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 635040, while the sum is 43.

The spelling of 1353342740173 in words is "one trillion, three hundred fifty-three billion, three hundred forty-two million, seven hundred forty thousand, one hundred seventy-three".