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1353347315561 is a prime number
BaseRepresentation
bin10011101100011001110…
…010010011011101101001
311210101020002201212120102
4103230121302103131221
5134133123403044221
62513415201435145
7166530131243543
oct23543162233551
94711202655512
101353347315561
11481a51306a3a
1219a35533bab5
139a80a4a4a57
1449706690693
152530c5b730b
hex13b19c93769

1353347315561 has 2 divisors, whose sum is σ = 1353347315562. Its totient is φ = 1353347315560.

The previous prime is 1353347315417. The next prime is 1353347315563. The reversal of 1353347315561 is 1655137433531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1230227032336 + 123120283225 = 1109156^2 + 350885^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1353347315561 is a prime.

Together with 1353347315563, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1353347315563) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 676673657780 + 676673657781.

It is an arithmetic number, because the mean of its divisors is an integer number (676673657781).

Almost surely, 21353347315561 is an apocalyptic number.

It is an amenable number.

1353347315561 is a deficient number, since it is larger than the sum of its proper divisors (1).

1353347315561 is an equidigital number, since it uses as much as digits as its factorization.

1353347315561 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1701000, while the sum is 47.

The spelling of 1353347315561 in words is "one trillion, three hundred fifty-three billion, three hundred forty-seven million, three hundred fifteen thousand, five hundred sixty-one".