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1353416103649 is a prime number
BaseRepresentation
bin10011101100011101111…
…000101101011011100001
311210101101220011200002101
4103230131320231123201
5134133244010304044
62513430100050401
7166531625032111
oct23543570553341
94711356150071
101353416103649
11481a8711a4a5
1219a374393a01
139a81b80aa6c
1449711879041
1525313653cd4
hex13b1de2d6e1

1353416103649 has 2 divisors, whose sum is σ = 1353416103650. Its totient is φ = 1353416103648.

The previous prime is 1353416103631. The next prime is 1353416103719. The reversal of 1353416103649 is 9463016143531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1346602426624 + 6813677025 = 1160432^2 + 82545^2 .

It is a cyclic number.

It is not a de Polignac number, because 1353416103649 - 27 = 1353416103521 is a prime.

It is a super-2 number, since 2×13534161036492 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1353416103599 and 1353416103608.

It is not a weakly prime, because it can be changed into another prime (1353416103049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 676708051824 + 676708051825.

It is an arithmetic number, because the mean of its divisors is an integer number (676708051825).

Almost surely, 21353416103649 is an apocalyptic number.

It is an amenable number.

1353416103649 is a deficient number, since it is larger than the sum of its proper divisors (1).

1353416103649 is an equidigital number, since it uses as much as digits as its factorization.

1353416103649 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 699840, while the sum is 46.

The spelling of 1353416103649 in words is "one trillion, three hundred fifty-three billion, four hundred sixteen million, one hundred three thousand, six hundred forty-nine".