Base | Representation |
---|---|
bin | 10011101100011110001… |
… | …000001100010000110111 |
3 | 11210101102011210212020111 |
4 | 103230132020030100313 |
5 | 134133301030141403 |
6 | 2513430323043451 |
7 | 166532004364252 |
oct | 23543610142067 |
9 | 4711364725214 |
10 | 1353420162103 |
11 | 481a89441699 |
12 | 19a375810587 |
13 | 9a81c5cc109 |
14 | 49712214099 |
15 | 25313ba656d |
hex | 13b1e20c437 |
1353420162103 has 4 divisors (see below), whose sum is σ = 1353444105880. Its totient is φ = 1353396218328.
The previous prime is 1353420162091. The next prime is 1353420162131. The reversal of 1353420162103 is 3012610243531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1353420162103 - 229 = 1352883291191 is a prime.
It is a super-2 number, since 2×13534201621032 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1353420163103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11886900 + ... + 12000217.
It is an arithmetic number, because the mean of its divisors is an integer number (338361026470).
Almost surely, 21353420162103 is an apocalyptic number.
1353420162103 is a deficient number, since it is larger than the sum of its proper divisors (23943777).
1353420162103 is an equidigital number, since it uses as much as digits as its factorization.
1353420162103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 23943776.
The product of its (nonzero) digits is 12960, while the sum is 31.
The spelling of 1353420162103 in words is "one trillion, three hundred fifty-three billion, four hundred twenty million, one hundred sixty-two thousand, one hundred three".
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