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1353431414653 = 3334340591171
BaseRepresentation
bin10011101100011110110…
…011000111011101111101
311210101102221222112211121
4103230132303013131331
5134133311420232103
62513431404150541
7166532202131443
oct23543663073575
94711387875747
101353431414653
11481a9482791a
1219a379538451
139a821a3bb26
1449713902b93
1525314b7a6bd
hex13b1ecc777d

1353431414653 has 4 divisors (see below), whose sum is σ = 1353472039168. Its totient is φ = 1353390790140.

The previous prime is 1353431414641. The next prime is 1353431414689. The reversal of 1353431414653 is 3564141343531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1353431414653 - 29 = 1353431414141 is a prime.

It is a super-2 number, since 2×13534314146532 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1353431414623) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20262243 + ... + 20328928.

It is an arithmetic number, because the mean of its divisors is an integer number (338368009792).

Almost surely, 21353431414653 is an apocalyptic number.

It is an amenable number.

1353431414653 is a deficient number, since it is larger than the sum of its proper divisors (40624515).

1353431414653 is an equidigital number, since it uses as much as digits as its factorization.

1353431414653 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 40624514.

The product of its digits is 777600, while the sum is 43.

The spelling of 1353431414653 in words is "one trillion, three hundred fifty-three billion, four hundred thirty-one million, four hundred fourteen thousand, six hundred fifty-three".

Divisors: 1 33343 40591171 1353431414653