1353433114199 has 2 divisors, whose sum is σ = 1353433114200. Its totient is φ = 1353433114198.

The previous prime is 1353433114193. The next prime is 1353433114247. The reversal of 1353433114199 is 9914113343531.

It is a weak prime.

It is an emirp because it is prime and its reverse (9914113343531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1353433114199 - 2⁸ = 1353433113943 is a prime.

It is a super-3 number, since 3×1353433114199³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1353433114193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 676716557099 + 676716557100.

It is an arithmetic number, because the mean of its divisors is an integer number (676716557100).

Almost surely, 2^{1353433114199} is an apocalyptic number.

1353433114199 is a deficient number, since it is larger than the sum of its proper divisors (1).

1353433114199 is an equidigital number, since it uses as much as digits as its factorization.

1353433114199 is an evil number, because the sum of its binary digits is even.

The product of its digits is 524880, while the sum is 47.

The spelling of 1353433114199 in words is "one trillion, three hundred fifty-three billion, four hundred thirty-three million, one hundred fourteen thousand, one hundred ninety-nine".