Base | Representation |
---|---|
bin | 1100010011110011011101… |
… | …1011111000111001001111 |
3 | 1202220212120122201010200221 |
4 | 3010330313123320321033 |
5 | 3233221343213220003 |
6 | 44441334335132211 |
7 | 2564553232620334 |
oct | 304746733707117 |
9 | 52825518633627 |
10 | 13534372007503 |
11 | 4348993181166 |
12 | 1627075974067 |
13 | 772393bacc69 |
14 | 34b0d21a298b |
15 | 1870d7b4d7bd |
hex | c4f376f8e4f |
13534372007503 has 2 divisors, whose sum is σ = 13534372007504. Its totient is φ = 13534372007502.
The previous prime is 13534372007479. The next prime is 13534372007531. The reversal of 13534372007503 is 30570027343531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13534372007503 - 213 = 13534371999311 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13534372007503.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13534372047503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6767186003751 + 6767186003752.
It is an arithmetic number, because the mean of its divisors is an integer number (6767186003752).
Almost surely, 213534372007503 is an apocalyptic number.
13534372007503 is a deficient number, since it is larger than the sum of its proper divisors (1).
13534372007503 is an equidigital number, since it uses as much as digits as its factorization.
13534372007503 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 793800, while the sum is 43.
The spelling of 13534372007503 in words is "thirteen trillion, five hundred thirty-four billion, three hundred seventy-two million, seven thousand, five hundred three".
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