Base | Representation |
---|---|
bin | 10011101100100011100… |
… | …110101110111010101001 |
3 | 11210101122120201110211102 |
4 | 103230203212232322221 |
5 | 134133443041220231 |
6 | 2513443404411145 |
7 | 166534201431041 |
oct | 23544346567251 |
9 | 4711576643742 |
10 | 1353512054441 |
11 | 4820262a5778 |
12 | 19a3a0546ab5 |
13 | 9a835664491 |
14 | 497204d4721 |
15 | 2531bca8acb |
hex | 13b239aeea9 |
1353512054441 has 2 divisors, whose sum is σ = 1353512054442. Its totient is φ = 1353512054440.
The previous prime is 1353512054429. The next prime is 1353512054497. The reversal of 1353512054441 is 1444502153531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1021759094041 + 331752960400 = 1010821^2 + 575980^2 .
It is a cyclic number.
It is not a de Polignac number, because 1353512054441 - 222 = 1353507860137 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1353512054395 and 1353512054404.
It is not a weakly prime, because it can be changed into another prime (1359512054441) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 676756027220 + 676756027221.
It is an arithmetic number, because the mean of its divisors is an integer number (676756027221).
Almost surely, 21353512054441 is an apocalyptic number.
It is an amenable number.
1353512054441 is a deficient number, since it is larger than the sum of its proper divisors (1).
1353512054441 is an equidigital number, since it uses as much as digits as its factorization.
1353512054441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144000, while the sum is 38.
The spelling of 1353512054441 in words is "one trillion, three hundred fifty-three billion, five hundred twelve million, fifty-four thousand, four hundred forty-one".
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