Base | Representation |
---|---|
bin | 11001001101100001… |
… | …01111101101100001 |
3 | 1021221021220010122021 |
4 | 30212300233231201 |
5 | 210210003330213 |
6 | 10115030341441 |
7 | 656262265366 |
oct | 144660575541 |
9 | 37837803567 |
10 | 13535214433 |
11 | 5816303a34 |
12 | 2758aba881 |
13 | 1379236330 |
14 | 92588a46d |
15 | 543423d8d |
hex | 326c2fb61 |
13535214433 has 16 divisors (see below), whose sum is σ = 15559689600. Its totient is φ = 11669736960.
The previous prime is 13535214419. The next prime is 13535214437. The reversal of 13535214433 is 33441253531.
It is a cyclic number.
It is not a de Polignac number, because 13535214433 - 29 = 13535213921 is a prime.
It is a super-2 number, since 2×135352144332 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13535214437) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 368368 + ... + 403441.
It is an arithmetic number, because the mean of its divisors is an integer number (972480600).
Almost surely, 213535214433 is an apocalyptic number.
13535214433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
13535214433 is a deficient number, since it is larger than the sum of its proper divisors (2024475167).
13535214433 is a wasteful number, since it uses less digits than its factorization.
13535214433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 771912.
The product of its digits is 64800, while the sum is 34.
Adding to 13535214433 its reverse (33441253531), we get a palindrome (46976467964).
The spelling of 13535214433 in words is "thirteen billion, five hundred thirty-five million, two hundred fourteen thousand, four hundred thirty-three".
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