Base | Representation |
---|---|
bin | 11001001101100100… |
… | …00010000111111001 |
3 | 1021221022112021200111 |
4 | 30212302002013321 |
5 | 210210100130433 |
6 | 10115041504321 |
7 | 656265202465 |
oct | 144662020771 |
9 | 37838467614 |
10 | 13535551993 |
11 | 5816514607 |
12 | 27590420a1 |
13 | 1379323b82 |
14 | 9259374a5 |
15 | 54348ddcd |
hex | 326c821f9 |
13535551993 has 2 divisors, whose sum is σ = 13535551994. Its totient is φ = 13535551992.
The previous prime is 13535551943. The next prime is 13535552021. The reversal of 13535551993 is 39915553531.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12625443769 + 910108224 = 112363^2 + 30168^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13535551993 is a prime.
It is a super-2 number, since 2×135355519932 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13535551943) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6767775996 + 6767775997.
It is an arithmetic number, because the mean of its divisors is an integer number (6767775997).
Almost surely, 213535551993 is an apocalyptic number.
It is an amenable number.
13535551993 is a deficient number, since it is larger than the sum of its proper divisors (1).
13535551993 is an equidigital number, since it uses as much as digits as its factorization.
13535551993 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1366875, while the sum is 49.
The spelling of 13535551993 in words is "thirteen billion, five hundred thirty-five million, five hundred fifty-one thousand, nine hundred ninety-three".
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