Base | Representation |
---|---|
bin | 10011101100101010000… |
… | …010101001011010010111 |
3 | 11210101221002220110121122 |
4 | 103230222002221122113 |
5 | 134134203212111343 |
6 | 2513502223034155 |
7 | 166536652312601 |
oct | 23545202513227 |
9 | 4711832813548 |
10 | 1353620035223 |
11 | 482081248295 |
12 | 19a41073b95b |
13 | 9a851b40731 |
14 | 497309a2171 |
15 | 253264d8068 |
hex | 13b2a0a9697 |
1353620035223 has 4 divisors (see below), whose sum is σ = 1359690080448. Its totient is φ = 1347549990000.
The previous prime is 1353620035219. The next prime is 1353620035247. The reversal of 1353620035223 is 3225300263531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1353620035223 - 22 = 1353620035219 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1353620035283) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3035022278 + ... + 3035022723.
It is an arithmetic number, because the mean of its divisors is an integer number (339922520112).
Almost surely, 21353620035223 is an apocalyptic number.
1353620035223 is a deficient number, since it is larger than the sum of its proper divisors (6070045225).
1353620035223 is an equidigital number, since it uses as much as digits as its factorization.
1353620035223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6070045224.
The product of its (nonzero) digits is 97200, while the sum is 35.
Adding to 1353620035223 its reverse (3225300263531), we get a palindrome (4578920298754).
The spelling of 1353620035223 in words is "one trillion, three hundred fifty-three billion, six hundred twenty million, thirty-five thousand, two hundred twenty-three".
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