Base | Representation |
---|---|
bin | 111111000010001001… |
… | …0110010010101010011 |
3 | 110221101201022110011111 |
4 | 1332010102302111103 |
5 | 4204211024102233 |
6 | 142103553354151 |
7 | 12531301536430 |
oct | 1760422622523 |
9 | 427351273144 |
10 | 135363503443 |
11 | 52453194703 |
12 | 22298b68957 |
13 | c9c31369cc |
14 | 67a1950b87 |
15 | 37c3b6eacd |
hex | 1f844b2553 |
135363503443 has 4 divisors (see below), whose sum is σ = 154701146800. Its totient is φ = 116025860088.
The previous prime is 135363503417. The next prime is 135363503453. The reversal of 135363503443 is 344305363531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 135363503443 - 221 = 135361406291 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 135363503396 and 135363503405.
It is not an unprimeable number, because it can be changed into a prime (135363503453) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9668821668 + ... + 9668821681.
It is an arithmetic number, because the mean of its divisors is an integer number (38675286700).
Almost surely, 2135363503443 is an apocalyptic number.
135363503443 is a deficient number, since it is larger than the sum of its proper divisors (19337643357).
135363503443 is an equidigital number, since it uses as much as digits as its factorization.
135363503443 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19337643356.
The product of its (nonzero) digits is 583200, while the sum is 40.
Adding to 135363503443 its reverse (344305363531), we get a palindrome (479668866974).
The spelling of 135363503443 in words is "one hundred thirty-five billion, three hundred sixty-three million, five hundred three thousand, four hundred forty-three".
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