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135363503453 is a prime number
BaseRepresentation
bin111111000010001001…
…0110010010101011101
3110221101201022110011212
41332010102302111131
54204211024102303
6142103553354205
712531301536443
oct1760422622535
9427351273155
10135363503453
1152453194712
1222298b68965
13c9c3136a09
1467a1950b93
1537c3b6ead8
hex1f844b255d

135363503453 has 2 divisors, whose sum is σ = 135363503454. Its totient is φ = 135363503452.

The previous prime is 135363503417. The next prime is 135363503501. The reversal of 135363503453 is 354305363531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 106408397209 + 28955106244 = 326203^2 + 170162^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-135363503453 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 135363503453.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (135363503053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67681751726 + 67681751727.

It is an arithmetic number, because the mean of its divisors is an integer number (67681751727).

Almost surely, 2135363503453 is an apocalyptic number.

It is an amenable number.

135363503453 is a deficient number, since it is larger than the sum of its proper divisors (1).

135363503453 is an equidigital number, since it uses as much as digits as its factorization.

135363503453 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 729000, while the sum is 41.

Adding to 135363503453 its reverse (354305363531), we get a palindrome (489668866984).

The spelling of 135363503453 in words is "one hundred thirty-five billion, three hundred sixty-three million, five hundred three thousand, four hundred fifty-three".