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135393312697 = 1063191273463
BaseRepresentation
bin111111000011000010…
…0011111111110111001
3110221110210101220202221
41332012010133332321
54204241142001242
6142110540324041
712532113112036
oct1760604377671
9427423356687
10135393312697
1152468aa4855
12222a6b43621
13c9c9372c16
1467a58b038d
1537c65ac167
hex1f8611ffb9

135393312697 has 4 divisors (see below), whose sum is σ = 135394692480. Its totient is φ = 135391932916.

The previous prime is 135393312671. The next prime is 135393312701. The reversal of 135393312697 is 796213393531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 135393312697 - 223 = 135384924089 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (135393312667) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 530413 + ... + 743050.

It is an arithmetic number, because the mean of its divisors is an integer number (33848673120).

Almost surely, 2135393312697 is an apocalyptic number.

It is an amenable number.

135393312697 is a deficient number, since it is larger than the sum of its proper divisors (1379783).

135393312697 is a wasteful number, since it uses less digits than its factorization.

135393312697 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1379782.

The product of its digits is 2755620, while the sum is 52.

The spelling of 135393312697 in words is "one hundred thirty-five billion, three hundred ninety-three million, three hundred twelve thousand, six hundred ninety-seven".

Divisors: 1 106319 1273463 135393312697