Base | Representation |
---|---|
bin | 10000001000111… |
… | …11110011001001 |
3 | 100102202212011011 |
4 | 20010133303021 |
5 | 234130142203 |
6 | 21234003521 |
7 | 3232565065 |
oct | 1004376311 |
9 | 312685134 |
10 | 135396553 |
11 | 6a478486 |
12 | 394165a1 |
13 | 22087c06 |
14 | 13da6aa5 |
15 | bd4776d |
hex | 811fcc9 |
135396553 has 2 divisors, whose sum is σ = 135396554. Its totient is φ = 135396552.
The previous prime is 135396529. The next prime is 135396557. The reversal of 135396553 is 355693531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 134838544 + 558009 = 11612^2 + 747^2 .
It is an emirp because it is prime and its reverse (355693531) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-135396553 is a prime.
It is not a weakly prime, because it can be changed into another prime (135396557) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67698276 + 67698277.
It is an arithmetic number, because the mean of its divisors is an integer number (67698277).
Almost surely, 2135396553 is an apocalyptic number.
It is an amenable number.
135396553 is a deficient number, since it is larger than the sum of its proper divisors (1).
135396553 is an equidigital number, since it uses as much as digits as its factorization.
135396553 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 182250, while the sum is 40.
The square root of 135396553 is about 11636.0024492950. The cubic root of 135396553 is about 513.4945863880.
The spelling of 135396553 in words is "one hundred thirty-five million, three hundred ninety-six thousand, five hundred fifty-three".
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