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135401996737 = 719343142391
BaseRepresentation
bin111111000011010010…
…1101000000111000001
3110221111101202010001001
41332012211220013001
54204300402343422
6142111450412001
712532246660660
oct1760645500701
9427441663031
10135401996737
1152472996247
12222a9a31001
13c9cb0c37c7
1467a6ad0dd7
1537c7225227
hex1f869681c1

135401996737 has 4 divisors (see below), whose sum is σ = 154745139136. Its totient is φ = 116058854340.

The previous prime is 135401996713. The next prime is 135401996747. The reversal of 135401996737 is 737699104531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-135401996737 is a prime.

It is not an unprimeable number, because it can be changed into a prime (135401996747) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9671571189 + ... + 9671571202.

It is an arithmetic number, because the mean of its divisors is an integer number (38686284784).

Almost surely, 2135401996737 is an apocalyptic number.

It is an amenable number.

135401996737 is a deficient number, since it is larger than the sum of its proper divisors (19343142399).

135401996737 is an equidigital number, since it uses as much as digits as its factorization.

135401996737 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19343142398.

The product of its (nonzero) digits is 4286520, while the sum is 55.

The spelling of 135401996737 in words is "one hundred thirty-five billion, four hundred one million, nine hundred ninety-six thousand, seven hundred thirty-seven".

Divisors: 1 7 19343142391 135401996737