Base | Representation |
---|---|
bin | 111111000011010010… |
… | …1101100010101000111 |
3 | 110221111101202222202021 |
4 | 1332012211230111013 |
5 | 4204300403422043 |
6 | 142111451024011 |
7 | 12532250062243 |
oct | 1760645542507 |
9 | 427441688667 |
10 | 135402014023 |
11 | 524729a8231 |
12 | 222a9a3b007 |
13 | c9cb0cb633 |
14 | 67a6ad7423 |
15 | 37c722a3ed |
hex | 1f8696c547 |
135402014023 has 2 divisors, whose sum is σ = 135402014024. Its totient is φ = 135402014022.
The previous prime is 135402013997. The next prime is 135402014071. The reversal of 135402014023 is 320410204531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 135402014023 - 225 = 135368459591 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135402054023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67701007011 + 67701007012.
It is an arithmetic number, because the mean of its divisors is an integer number (67701007012).
Almost surely, 2135402014023 is an apocalyptic number.
135402014023 is a deficient number, since it is larger than the sum of its proper divisors (1).
135402014023 is an equidigital number, since it uses as much as digits as its factorization.
135402014023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 135402014023 its reverse (320410204531), we get a palindrome (455812218554).
The spelling of 135402014023 in words is "one hundred thirty-five billion, four hundred two million, fourteen thousand, twenty-three".
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