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13540201403 = 73302361357
BaseRepresentation
bin11001001110000111…
…10001001110111011
31021221122021111110212
430213003301032323
5210212242421103
610115325301335
7656352545561
oct144703611673
937848244425
1013540201403
1158190aa7a3
12275a70484b
13137a2911c1
149263c7a31
15543aab7d8
hex3270f13bb

13540201403 has 8 divisors (see below), whose sum is σ = 13730447808. Its totient is φ = 13350083904.

The previous prime is 13540201399. The next prime is 13540201469. The reversal of 13540201403 is 30410204531.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13540201403 - 22 = 13540201399 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13540201303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 190001 + ... + 251357.

It is an arithmetic number, because the mean of its divisors is an integer number (1716305976).

Almost surely, 213540201403 is an apocalyptic number.

13540201403 is a deficient number, since it is larger than the sum of its proper divisors (190246405).

13540201403 is an equidigital number, since it uses as much as digits as its factorization.

13540201403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 64453.

The product of its (nonzero) digits is 1440, while the sum is 23.

Adding to 13540201403 its reverse (30410204531), we get a palindrome (43950405934).

The spelling of 13540201403 in words is "thirteen billion, five hundred forty million, two hundred one thousand, four hundred three".

Divisors: 1 73 3023 61357 220679 4479061 185482211 13540201403