Base | Representation |
---|---|
bin | 10011101101000001111… |
… | …111001001001101110111 |
3 | 11210102222002211201021021 |
4 | 103231001333021031313 |
5 | 134141014033120403 |
6 | 2514010133402011 |
7 | 166552631101402 |
oct | 23550177111567 |
9 | 4712862751237 |
10 | 1354021770103 |
11 | 482267a98692 |
12 | 19a503199307 |
13 | 9a8b713b892 |
14 | 4976c098d39 |
15 | 2534b8e08bd |
hex | 13b41fc9377 |
1354021770103 has 2 divisors, whose sum is σ = 1354021770104. Its totient is φ = 1354021770102.
The previous prime is 1354021770037. The next prime is 1354021770113. The reversal of 1354021770103 is 3010771204531.
It is a strong prime.
It is an emirp because it is prime and its reverse (3010771204531) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1354021770103 is a prime.
It is a super-2 number, since 2×13540217701032 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1354021770113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677010885051 + 677010885052.
It is an arithmetic number, because the mean of its divisors is an integer number (677010885052).
Almost surely, 21354021770103 is an apocalyptic number.
1354021770103 is a deficient number, since it is larger than the sum of its proper divisors (1).
1354021770103 is an equidigital number, since it uses as much as digits as its factorization.
1354021770103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17640, while the sum is 34.
Adding to 1354021770103 its reverse (3010771204531), we get a palindrome (4364792974634).
The spelling of 1354021770103 in words is "one trillion, three hundred fifty-four billion, twenty-one million, seven hundred seventy thousand, one hundred three".
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