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1354021770103 is a prime number
BaseRepresentation
bin10011101101000001111…
…111001001001101110111
311210102222002211201021021
4103231001333021031313
5134141014033120403
62514010133402011
7166552631101402
oct23550177111567
94712862751237
101354021770103
11482267a98692
1219a503199307
139a8b713b892
144976c098d39
152534b8e08bd
hex13b41fc9377

1354021770103 has 2 divisors, whose sum is σ = 1354021770104. Its totient is φ = 1354021770102.

The previous prime is 1354021770037. The next prime is 1354021770113. The reversal of 1354021770103 is 3010771204531.

It is a strong prime.

It is an emirp because it is prime and its reverse (3010771204531) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1354021770103 is a prime.

It is a super-2 number, since 2×13540217701032 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1354021770113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677010885051 + 677010885052.

It is an arithmetic number, because the mean of its divisors is an integer number (677010885052).

Almost surely, 21354021770103 is an apocalyptic number.

1354021770103 is a deficient number, since it is larger than the sum of its proper divisors (1).

1354021770103 is an equidigital number, since it uses as much as digits as its factorization.

1354021770103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17640, while the sum is 34.

Adding to 1354021770103 its reverse (3010771204531), we get a palindrome (4364792974634).

The spelling of 1354021770103 in words is "one trillion, three hundred fifty-four billion, twenty-one million, seven hundred seventy thousand, one hundred three".