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1354041153 = 32227662771
BaseRepresentation
bin101000010110101…
…0000011101000001
310111100212102021100
41100231100131001
510233113304103
6342205445013
745361105563
oct12055203501
93440772240
101354041153
11635359183
12319570769
131876a98aa
14cbb8b333
157dd175a3
hex50b50741

1354041153 has 12 divisors (see below), whose sum is σ = 1964456208. Its totient is φ = 898716120.

The previous prime is 1354041133. The next prime is 1354041203. The reversal of 1354041153 is 3511404531.

It is a happy number.

1354041153 is a `hidden beast` number, since 1 + 3 + 540 + 4 + 115 + 3 = 666.

It is not a de Polignac number, because 1354041153 - 26 = 1354041089 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1354041103) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 329343 + ... + 333428.

It is an arithmetic number, because the mean of its divisors is an integer number (163704684).

Almost surely, 21354041153 is an apocalyptic number.

It is an amenable number.

1354041153 is a deficient number, since it is larger than the sum of its proper divisors (610415055).

1354041153 is a wasteful number, since it uses less digits than its factorization.

1354041153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 663004 (or 663001 counting only the distinct ones).

The product of its (nonzero) digits is 3600, while the sum is 27.

The square root of 1354041153 is about 36797.2981752737. The cubic root of 1354041153 is about 1106.3111462132.

Adding to 1354041153 its reverse (3511404531), we get a palindrome (4865445684).

The spelling of 1354041153 in words is "one billion, three hundred fifty-four million, forty-one thousand, one hundred fifty-three".

Divisors: 1 3 9 227 681 2043 662771 1988313 5964939 150449017 451347051 1354041153