13540441 has 4 divisors (see below), whose sum is σ = 13770000. Its totient is φ = 13310884.

The previous prime is 13540433. The next prime is 13540463. The reversal of 13540441 is 14404531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14404531 = 67 ⋅214993.

It is a cyclic number.

It is not a de Polignac number, because 13540441 - 2³ = 13540433 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13540411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 114691 + ... + 114808.

It is an arithmetic number, because the mean of its divisors is an integer number (3442500).

Almost surely, 2^13540441 is an apocalyptic number.

It is an amenable number.

13540441 is a deficient number, since it is larger than the sum of its proper divisors (229559).

13540441 is an equidigital number, since it uses as much as digits as its factorization.

13540441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 229558.

The product of its (nonzero) digits is 960, while the sum is 22.

The square root of 13540441 is about 3679.7338218953. The cubic root of 13540441 is about 238.3476840539.

Adding to 13540441 its reverse (14404531), we get a palindrome (27944972).

The spelling of 13540441 in words is "thirteen million, five hundred forty thousand, four hundred forty-one".