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1354052714753 is a prime number
BaseRepresentation
bin10011101101000011110…
…101001100000100000001
311210110001021001212100102
4103231003311030010001
5134141044443333003
62514013200532145
7166553455113134
oct23550365140401
94713037055312
101354052714753
11482283503882
1219a511621055
139a8c068481b
144977223221b
152534e4a4588
hex13b43d4c101

1354052714753 has 2 divisors, whose sum is σ = 1354052714754. Its totient is φ = 1354052714752.

The previous prime is 1354052714741. The next prime is 1354052714797. The reversal of 1354052714753 is 3574172504531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1112113666624 + 241939048129 = 1054568^2 + 491873^2 .

It is a cyclic number.

It is not a de Polignac number, because 1354052714753 - 230 = 1352978972929 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1354052714698 and 1354052714707.

It is not a weakly prime, because it can be changed into another prime (1354052714153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677026357376 + 677026357377.

It is an arithmetic number, because the mean of its divisors is an integer number (677026357377).

Almost surely, 21354052714753 is an apocalyptic number.

It is an amenable number.

1354052714753 is a deficient number, since it is larger than the sum of its proper divisors (1).

1354052714753 is an equidigital number, since it uses as much as digits as its factorization.

1354052714753 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1764000, while the sum is 47.

The spelling of 1354052714753 in words is "one trillion, three hundred fifty-four billion, fifty-two million, seven hundred fourteen thousand, seven hundred fifty-three".