Base | Representation |
---|---|
bin | 10011101101000110110… |
… | …001101111110001011101 |
3 | 11210110011201002010122201 |
4 | 103231012301233301131 |
5 | 134141200122102333 |
6 | 2514022124211501 |
7 | 166554625213036 |
oct | 23550661576135 |
9 | 4713151063581 |
10 | 1354102144093 |
11 | 4822a93a4876 |
12 | 19a526099b91 |
13 | 9a8ca9a025a |
14 | 49778a1ba8d |
15 | 253539ba17d |
hex | 13b46c6fc5d |
1354102144093 has 2 divisors, whose sum is σ = 1354102144094. Its totient is φ = 1354102144092.
The previous prime is 1354102144069. The next prime is 1354102144147. The reversal of 1354102144093 is 3904412014531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 694152252964 + 659949891129 = 833158^2 + 812373^2 .
It is a cyclic number.
It is not a de Polignac number, because 1354102144093 - 217 = 1354102013021 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1354102144063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677051072046 + 677051072047.
It is an arithmetic number, because the mean of its divisors is an integer number (677051072047).
Almost surely, 21354102144093 is an apocalyptic number.
It is an amenable number.
1354102144093 is a deficient number, since it is larger than the sum of its proper divisors (1).
1354102144093 is an equidigital number, since it uses as much as digits as its factorization.
1354102144093 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 51840, while the sum is 37.
The spelling of 1354102144093 in words is "one trillion, three hundred fifty-four billion, one hundred two million, one hundred forty-four thousand, ninety-three".
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