135410501003 has 4 divisors (see below), whose sum is σ = 135411556680. Its totient is φ = 135409445328.

The previous prime is 135410500999. The next prime is 135410501011. The reversal of 135410501003 is 300105014531.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 135410501003 - 2² = 135410500999 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 135410501003.

It is not an unprimeable number, because it can be changed into a prime (135410501033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 303713 + ... + 602546.

It is an arithmetic number, because the mean of its divisors is an integer number (33852889170).

Almost surely, 2^135410501003 is an apocalyptic number.

135410501003 is a deficient number, since it is larger than the sum of its proper divisors (1055677).

135410501003 is an equidigital number, since it uses as much as digits as its factorization.

135410501003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1055676.

The product of its (nonzero) digits is 900, while the sum is 23.

Adding to 135410501003 its reverse (300105014531), we get a palindrome (435515515534).

The spelling of 135410501003 in words is "one hundred thirty-five billion, four hundred ten million, five hundred one thousand, three".