Base | Representation |
---|---|
bin | 10011101101000111010… |
… | …011101011111101111011 |
3 | 11210110012022211011110201 |
4 | 103231013103223331323 |
5 | 134141204411311103 |
6 | 2514023043023031 |
7 | 166555063640521 |
oct | 23550723537573 |
9 | 4713168734421 |
10 | 1354111041403 |
11 | 48230342151a |
12 | 19a52906aa77 |
13 | 9a8cc796c33 |
14 | 49779c96311 |
15 | 2535467651d |
hex | 13b474ebf7b |
1354111041403 has 2 divisors, whose sum is σ = 1354111041404. Its totient is φ = 1354111041402.
The previous prime is 1354111041397. The next prime is 1354111041431. The reversal of 1354111041403 is 3041401114531.
It is an a-pointer prime, because the next prime (1354111041431) can be obtained adding 1354111041403 to its sum of digits (28).
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1354111041403 is a prime.
It is not a weakly prime, because it can be changed into another prime (1354111045403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677055520701 + 677055520702.
It is an arithmetic number, because the mean of its divisors is an integer number (677055520702).
Almost surely, 21354111041403 is an apocalyptic number.
1354111041403 is a deficient number, since it is larger than the sum of its proper divisors (1).
1354111041403 is an equidigital number, since it uses as much as digits as its factorization.
1354111041403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2880, while the sum is 28.
Adding to 1354111041403 its reverse (3041401114531), we get a palindrome (4395512155934).
The spelling of 1354111041403 in words is "one trillion, three hundred fifty-four billion, one hundred eleven million, forty-one thousand, four hundred three".
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