135411140471 has 4 divisors (see below), whose sum is σ = 135412129944. Its totient is φ = 135410151000.

The previous prime is 135411140443. The next prime is 135411140503. The reversal of 135411140471 is 174041114531.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 174041114531 = 31 ⋅5614229501.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-135411140471 is a prime.

It is a super-3 number, since 3×135411140471³ (a number of 34 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (135411140411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 248660 + ... + 576761.

It is an arithmetic number, because the mean of its divisors is an integer number (33853032486).

Almost surely, 2^135411140471 is an apocalyptic number.

135411140471 is a deficient number, since it is larger than the sum of its proper divisors (989473).

135411140471 is an equidigital number, since it uses as much as digits as its factorization.

135411140471 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 989472.

The product of its (nonzero) digits is 6720, while the sum is 32.

The spelling of 135411140471 in words is "one hundred thirty-five billion, four hundred eleven million, one hundred forty thousand, four hundred seventy-one".