135411433 has 4 divisors (see below), whose sum is σ = 135453060. Its totient is φ = 135369808.

The previous prime is 135411391. The next prime is 135411439. The reversal of 135411433 is 334114531.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 334114531 = 601 ⋅555931.

It can be written as a sum of positive squares in 2 ways, for example, as 48399849 + 87011584 = 6957^2 + 9328^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-135411433 is a prime.

It is a super-2 number, since 2×135411433² = 36672512374226978, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 135411398 and 135411407.

It is not an unprimeable number, because it can be changed into a prime (135411439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15478 + ... + 22591.

It is an arithmetic number, because the mean of its divisors is an integer number (33863265).

Almost surely, 2^135411433 is an apocalyptic number.

It is an amenable number.

135411433 is a deficient number, since it is larger than the sum of its proper divisors (41627).

135411433 is an equidigital number, since it uses as much as digits as its factorization.

135411433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 41626.

The product of its digits is 2160, while the sum is 25.

The square root of 135411433 is about 11636.6418265752. The cubic root of 135411433 is about 513.5133966147.

Adding to 135411433 its reverse (334114531), we get a palindrome (469525964).

The spelling of 135411433 in words is "one hundred thirty-five million, four hundred eleven thousand, four hundred thirty-three".