Base | Representation |
---|---|
bin | 11110110010100000000000… |
… | …011101000000111111101011 |
3 | 122202110020100202000111102111 |
4 | 132302200000131000333223 |
5 | 120222041214021431124 |
6 | 1155555143140543151 |
7 | 40344114031122322 |
oct | 3662400035007753 |
9 | 582406322014374 |
10 | 135411736514539 |
11 | 3a1678820a4181 |
12 | 1322b8506b1ab7 |
13 | 5a7336c667734 |
14 | 2561d6a7390b9 |
15 | 109c583c39494 |
hex | 7b2800740feb |
135411736514539 has 2 divisors, whose sum is σ = 135411736514540. Its totient is φ = 135411736514538.
The previous prime is 135411736514521. The next prime is 135411736514557. The reversal of 135411736514539 is 935415637114531.
It is a balanced prime because it is at equal distance from previous prime (135411736514521) and next prime (135411736514557).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-135411736514539 is a prime.
It is not a weakly prime, because it can be changed into another prime (135411736511539) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67705868257269 + 67705868257270.
It is an arithmetic number, because the mean of its divisors is an integer number (67705868257270).
Almost surely, 2135411736514539 is an apocalyptic number.
135411736514539 is a deficient number, since it is larger than the sum of its proper divisors (1).
135411736514539 is an equidigital number, since it uses as much as digits as its factorization.
135411736514539 is an evil number, because the sum of its binary digits is even.
The product of its digits is 20412000, while the sum is 58.
The spelling of 135411736514539 in words is "one hundred thirty-five trillion, four hundred eleven billion, seven hundred thirty-six million, five hundred fourteen thousand, five hundred thirty-nine".
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