Base | Representation |
---|---|
bin | 11110110010100011011101… |
… | …011001110001101110111110 |
3 | 122202110120221002020022221002 |
4 | 132302203131121301232332 |
5 | 120222121312004232314 |
6 | 1200000555041010302 |
7 | 40344304632312104 |
oct | 3662433531615676 |
9 | 582416832208832 |
10 | 135415443430334 |
11 | 3a1694045a7951 |
12 | 13230506023992 |
13 | 5a73810640132 |
14 | 25621dcb99c74 |
15 | 109c6ee3b9ade |
hex | 7b28dd671bbe |
135415443430334 has 4 divisors (see below), whose sum is σ = 203123165145504. Its totient is φ = 67707721715166.
The previous prime is 135415443430307. The next prime is 135415443430481. The reversal of 135415443430334 is 433034344514531.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×1354154434303342 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33853860857582 + ... + 33853860857585.
It is an arithmetic number, because the mean of its divisors is an integer number (50780791286376).
Almost surely, 2135415443430334 is an apocalyptic number.
135415443430334 is a deficient number, since it is larger than the sum of its proper divisors (67707721715170).
135415443430334 is an equidigital number, since it uses as much as digits as its factorization.
135415443430334 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 67707721715169.
The product of its (nonzero) digits is 6220800, while the sum is 47.
Adding to 135415443430334 its reverse (433034344514531), we get a palindrome (568449787944865).
The spelling of 135415443430334 in words is "one hundred thirty-five trillion, four hundred fifteen billion, four hundred forty-three million, four hundred thirty thousand, three hundred thirty-four".
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