Base | Representation |
---|---|
bin | 111111000011110110… |
… | …0000101000111010111 |
3 | 110221112200111102120212 |
4 | 1332013230011013113 |
5 | 4204320114344443 |
6 | 142113350320035 |
7 | 12532562652062 |
oct | 1760754050727 |
9 | 427480442525 |
10 | 135420465623 |
11 | 52482360193 |
12 | 222b405901b |
13 | ca01b8c041 |
14 | 67a933b8d9 |
15 | 37c8b72618 |
hex | 1f87b051d7 |
135420465623 has 2 divisors, whose sum is σ = 135420465624. Its totient is φ = 135420465622.
The previous prime is 135420465619. The next prime is 135420465671. The reversal of 135420465623 is 326564024531.
It is a weak prime.
It is an emirp because it is prime and its reverse (326564024531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 135420465623 - 22 = 135420465619 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135420465683) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67710232811 + 67710232812.
It is an arithmetic number, because the mean of its divisors is an integer number (67710232812).
Almost surely, 2135420465623 is an apocalyptic number.
135420465623 is a deficient number, since it is larger than the sum of its proper divisors (1).
135420465623 is an equidigital number, since it uses as much as digits as its factorization.
135420465623 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 518400, while the sum is 41.
The spelling of 135420465623 in words is "one hundred thirty-five billion, four hundred twenty million, four hundred sixty-five thousand, six hundred twenty-three".
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