Base | Representation |
---|---|
bin | 11110110010101000001101… |
… | …111101011100001110111011 |
3 | 122202111002010011220001200021 |
4 | 132302220031331130032323 |
5 | 120222212243040144430 |
6 | 1200003202045551311 |
7 | 40344545355350401 |
oct | 3662501575341673 |
9 | 582432104801607 |
10 | 135420553053115 |
11 | 3a1705968790a0 |
12 | 132314b1275537 |
13 | 5a74146101475 |
14 | 2562565635471 |
15 | 109c8ecc7707a |
hex | 7b2a0df5c3bb |
135420553053115 has 16 divisors (see below), whose sum is σ = 177281022378240. Its totient is φ = 98485893018720.
The previous prime is 135420553053113. The next prime is 135420553053127. The reversal of 135420553053115 is 511350355024531.
It is not a de Polignac number, because 135420553053115 - 21 = 135420553053113 is a prime.
It is a super-2 number, since 2×1354205530531152 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (135420553053113) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 19202799 + ... + 25290088.
It is an arithmetic number, because the mean of its divisors is an integer number (11080063898640).
Almost surely, 2135420553053115 is an apocalyptic number.
135420553053115 is a deficient number, since it is larger than the sum of its proper divisors (41860469325125).
135420553053115 is a wasteful number, since it uses less digits than its factorization.
135420553053115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44548242.
The product of its (nonzero) digits is 675000, while the sum is 43.
The spelling of 135420553053115 in words is "one hundred thirty-five trillion, four hundred twenty billion, five hundred fifty-three million, fifty-three thousand, one hundred fifteen".
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