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13542112531 is a prime number
BaseRepresentation
bin11001001110010110…
…00011110100010011
31021221202212121001101
430213023003310103
5210213240100111
610115434245231
7656405025433
oct144713036423
937852777041
1013542112531
11581a195642
12275b286817
13137a7b004c
149267642c3
15543d37bc1
hex3272c3d13

13542112531 has 2 divisors, whose sum is σ = 13542112532. Its totient is φ = 13542112530.

The previous prime is 13542112483. The next prime is 13542112541. The reversal of 13542112531 is 13521124531.

13542112531 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (13521124531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13542112531 - 27 = 13542112403 is a prime.

It is a super-2 number, since 2×135421125312 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13542112531.

It is not a weakly prime, because it can be changed into another prime (13542112541) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6771056265 + 6771056266.

It is an arithmetic number, because the mean of its divisors is an integer number (6771056266).

Almost surely, 213542112531 is an apocalyptic number.

13542112531 is a deficient number, since it is larger than the sum of its proper divisors (1).

13542112531 is an equidigital number, since it uses as much as digits as its factorization.

13542112531 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3600, while the sum is 28.

The spelling of 13542112531 in words is "thirteen billion, five hundred forty-two million, one hundred twelve thousand, five hundred thirty-one".