Base | Representation |
---|---|
bin | 11001001110010110… |
… | …00011110100100000 |
3 | 1021221202212121001212 |
4 | 30213023003310200 |
5 | 210213240100134 |
6 | 10115434245252 |
7 | 656405025452 |
oct | 144713036440 |
9 | 37852777055 |
10 | 13542112544 |
11 | 581a195654 |
12 | 275b286828 |
13 | 137a7b005c |
14 | 9267642d2 |
15 | 543d37bce |
hex | 3272c3d20 |
13542112544 has 12 divisors (see below), whose sum is σ = 26661034134. Its totient is φ = 6771056256.
The previous prime is 13542112541. The next prime is 13542112547. The reversal of 13542112544 is 44521124531.
It is an interprime number because it is at equal distance from previous prime (13542112541) and next prime (13542112547).
It can be written as a sum of positive squares in only one way, i.e., 9484422544 + 4057690000 = 97388^2 + 63700^2 .
It is a Harshad number since it is a multiple of its sum of digits (32), and also a Moran number because the ratio is a prime number: 423191017 = 13542112544 / (1 + 3 + 5 + 4 + 2 + 1 + 1 + 2 + 5 + 4 + 4).
It is a self number, because there is not a number n which added to its sum of digits gives 13542112544.
It is not an unprimeable number, because it can be changed into a prime (13542112541) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 211595477 + ... + 211595540.
Almost surely, 213542112544 is an apocalyptic number.
It is an amenable number.
13542112544 is a deficient number, since it is larger than the sum of its proper divisors (13118921590).
13542112544 is an equidigital number, since it uses as much as digits as its factorization.
13542112544 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 423191027 (or 423191019 counting only the distinct ones).
The product of its digits is 19200, while the sum is 32.
The spelling of 13542112544 in words is "thirteen billion, five hundred forty-two million, one hundred twelve thousand, five hundred forty-four".
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