Base | Representation |
---|---|
bin | 11110110010101010100000… |
… | …101010001010011000100111 |
3 | 122202111022110201001211010022 |
4 | 132302222200222022120213 |
5 | 120222232313122000043 |
6 | 1200004250205545355 |
7 | 40344663352234523 |
oct | 3662524052123047 |
9 | 582438421054108 |
10 | 135423014250023 |
11 | 3a17163a089825 |
12 | 13231a7957525b |
13 | 5a74448c95ab6 |
14 | 256271a464d83 |
15 | 109c9e3d8a868 |
hex | 7b2aa0a8a627 |
135423014250023 has 2 divisors, whose sum is σ = 135423014250024. Its totient is φ = 135423014250022.
The previous prime is 135423014249983. The next prime is 135423014250037. The reversal of 135423014250023 is 320052410324531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 135423014250023 - 26 = 135423014249959 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135423014150023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67711507125011 + 67711507125012.
It is an arithmetic number, because the mean of its divisors is an integer number (67711507125012).
Almost surely, 2135423014250023 is an apocalyptic number.
135423014250023 is a deficient number, since it is larger than the sum of its proper divisors (1).
135423014250023 is an equidigital number, since it uses as much as digits as its factorization.
135423014250023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 135423014250023 its reverse (320052410324531), we get a palindrome (455475424574554).
The spelling of 135423014250023 in words is "one hundred thirty-five trillion, four hundred twenty-three billion, fourteen million, two hundred fifty thousand, twenty-three".
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