Base | Representation |
---|---|
bin | 11001001110010111… |
… | …11100100110001111 |
3 | 1021221210022102002011 |
4 | 30213023330212033 |
5 | 210213320020403 |
6 | 10115443242051 |
7 | 656410014460 |
oct | 144713744617 |
9 | 37853272064 |
10 | 13542345103 |
11 | 581a334351 |
12 | 275b379327 |
13 | 137a861b71 |
14 | 9267c4d67 |
15 | 543d81a6d |
hex | 3272fc98f |
13542345103 has 4 divisors (see below), whose sum is σ = 15476965840. Its totient is φ = 11607724368.
The previous prime is 13542345101. The next prime is 13542345139. The reversal of 13542345103 is 30154324531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13542345103 - 21 = 13542345101 is a prime.
It is a super-2 number, since 2×135423451032 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13542345101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 967310358 + ... + 967310371.
It is an arithmetic number, because the mean of its divisors is an integer number (3869241460).
Almost surely, 213542345103 is an apocalyptic number.
13542345103 is a deficient number, since it is larger than the sum of its proper divisors (1934620737).
13542345103 is an equidigital number, since it uses as much as digits as its factorization.
13542345103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1934620736.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 13542345103 its reverse (30154324531), we get a palindrome (43696669634).
The spelling of 13542345103 in words is "thirteen billion, five hundred forty-two million, three hundred forty-five thousand, one hundred three".
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