Base | Representation |
---|---|
bin | 11110110010101011110101… |
… | …000111111001001011000111 |
3 | 122202111110010110112221101120 |
4 | 132302223311013321023013 |
5 | 120222243213410024431 |
6 | 1200005042550525023 |
7 | 40345043440225146 |
oct | 3662536507711307 |
9 | 582443113487346 |
10 | 135424431329991 |
11 | 3a1721a6a839a1 |
12 | 132321b4066773 |
13 | 5a7461374485b |
14 | 256281274175d |
15 | 109ca784a6196 |
hex | 7b2af51f92c7 |
135424431329991 has 4 divisors (see below), whose sum is σ = 180565908439992. Its totient is φ = 90282954219992.
The previous prime is 135424431329909. The next prime is 135424431330011. The reversal of 135424431329991 is 199923134424531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 135424431329991 - 215 = 135424431297223 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (135424431329791) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22570738554996 + ... + 22570738555001.
It is an arithmetic number, because the mean of its divisors is an integer number (45141477109998).
Almost surely, 2135424431329991 is an apocalyptic number.
135424431329991 is a deficient number, since it is larger than the sum of its proper divisors (45141477110001).
135424431329991 is an equidigital number, since it uses as much as digits as its factorization.
135424431329991 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 45141477110000.
The product of its digits is 25194240, while the sum is 60.
The spelling of 135424431329991 in words is "one hundred thirty-five trillion, four hundred twenty-four billion, four hundred thirty-one million, three hundred twenty-nine thousand, nine hundred ninety-one".
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